Test Bank for Microbiology, An Introduction, 13th Edition, Gerard J. Tortora, Berdell R. Funke, Christine L. Case, Derek Weber, Warner Bair

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Sample Questions from Microbiology an Introduction Tortora

Chapter 8   Microbial Genetics 13th ed Test Bank

8.1    Multiple-Choice Questions

1)  A gene is defined as

A) any random segment of DNA.

B) three nucleotides that code for an amino acid.

C) a sequence of nucleotides in DNA that codes for a functional product. D) a sequence of nucleotides in RNA that codes for a functional product. E) the RNA product of a transcribed section of DNA.

Answer:C Section:8.1

 2)  Which of the following pairs is mismatched?

A) DNA polymerase – makes a molecule of DNA from a DNA template B) RNA polymerase – makes a molecule of RNA from an RNA template C) DNA ligase – joins segments of DNA

D) transposase – cuts DNA backbone, leaving "sticky ends"

E) DNA gyrase – relaxes supercoiling in DNA ahead of the replication fork

Answer:  B Section:  8.1

Bloom's Taxonomy:  Remembering

Learning Outcome:  8.3

3)  Which of the following statements is FALSE?

A) DNA polymerase joins nucleotides in one direction (5' to 3') only. B) The leading strand of DNA is made continuously.

C) The lagging strand of DNA is started by an RNA primer.

D) DNA replication proceeds in only one direction around the bacterial chromosome. E) Multiple replication forks are possible on a bacterial chromosome.

Answer:  D

4)  DNA is constructed of

A) a single strand of nucleotides with internal hydrogen bonding.

B) two complementary strands of nucleotides bonded A–C and G–T. C) two strands of nucleotides running in an antiparallel configuration.

D) two strands of identical nucleotides in a parallel configuration with hydrogen bonds between them.

E) None of the answers is correct. Answer:  C

Section:  8.1

Bloom's Taxonomy:  Understanding

Learning Outcome:  8.2

Global Outcome:  2

5)  Which of the following is NOT a product of transcription? A) a new strand of DNA

B) rRNA C) tRNA D) mRNA

Answer:  A Section:  8.1

Bloom's Taxonomy:  Understanding

Learning Outcome:  8.4

6)  Which of the following statements about bacteriocins is FALSE? A) The genes coding for them are on plasmids.

B) They cause food-poisoning symptoms.

C) They can be used to identify certain bacteria. D) Bacteriocins kill bacteria.

Answer:  B Section:  8.4

Bloom's Taxonomy:  Understanding

Learning Outcome:  8.16

Global Outcome:  7

7)  Figure 8.1

In Figure 8.1, which colonies are streptomycin-resistant and leucine-requiring? A) 1, 2, 3, and 9

B) 3 and 9

C) 4, 6, and 8

D) 4 and 8

E) 5 and 6

Answer:  D Section:  8.3

Bloom's Taxonomy:  Analyzing

ASMcue Outcome:  4.1

Learning Outcome:  8.12

Global Outcome:  2

Table 8.1

Culture 1: F+, leucine+, histidine+ Culture 2: F-, leucine-, histidine-

8)  In Table 8.1, what will be the result of conjugation between cultures 1 and 2 (reminder: F+

has a different meaning than Hfr)? A) 1 will remain the same;

2 will become F+, leucine-, histidineB)

1 will become F-, leu+, his+;

2 will become F+, leu-, his-

C) 1 will become F-, leu-, his-;

 2  will remain the same

D) 1 will remain the same;

2 will become F+, leu+, his+ E) 1 will remain the same;

2 will become F+ and recombination may occur

Answer:  A Section:  8.4

Bloom's Taxonomy:  Analyzing

ASMcue Outcome:  4.1

Learning Outcome:  8.15

Global Outcome:  2

9) In Table 8.1, if culture 1 mutates to Hfr, what will be the result of conjugation between the two cultures?

A) They will both remain the same. B) 1 will become F+, leu+, his+;

2 will become F+, leu+, his+ C) 1 will remain the same; recombination may occur in 2

D) 1 will become F-, leu+, his+;

2  will become Hfr, leu+, his +

E) The answer cannot be determined based on the information provided. Answer:  C

Section:  8.4

Bloom's Taxonomy:  Analyzing

ASMcue Outcome:  4.1

Learning Outcome:  8.15

Global Outcome:  2

10)  An enzyme produced in response to the presence of a substrate is called a(n ) A) inducible enzyme.

B) repressible enzyme. C) restriction enzyme. D) operator.

E) promoter.

Answer:  A Section:  8.2

Bloom's Taxonomy:  Remembering

ASMcue Outcome:  4.3

Learning Outcome:  8.7

11)  Transformation is the transfer of DNA from a donor to a recipient cell

A) by a bacteriophage.

B) as naked DNA in solution.

C) by cell-to-cell contact. D) by crossing over.

E) by sexual reproduction. Answer:  B

Section:  8.4

Bloom's Taxonomy:  Remembering

ASMcue Outcome:  4.1

Learning Outcome:  8.15

12)  Genetic change in bacteria can be brought about by

A) mutation.

B) conjugation. C) transduction.

D) transformation.

E) All of the answers are correct. Answer:  E

Section:  8.4

Bloom's Taxonomy:  Understanding

ASMcue Outcome:  4.1

Learning Outcome:  8.15

13) Which of the following statements regarding a bacterium that is R+ is FALSE? A) It possesses a plasmid.

B) R+ can be transferred to a cell of the same species. C) It is resistant to certain drugs and heavy metals.

D) It is F+.

E) R+ can be transferred to a different species. Answer:  D

Section:  8.4

Bloom's Taxonomy:  Understanding

ASMcue Outcome:  4.1

Learning Outcome:  8.16

14)  The initial/first effect of ionizing radiation on a cell is that it causes

A) DNA to break.

B) bonding between adjacent thymines. C) base substitutions.

D) the formation of highly reactive ions. E) the cells to get hot.

Answer:  D Section:  8.3

Bloom's Taxonomy:  Remembering

Learning Outcome:  8.9

 15)  According to the operon model, for the synthesis of an inducible enzyme to occur, the

A) end-product must not be in excess. B) substrate must bind to the enzyme. C) substrate must bind to the repressor. D) repressor must bind to the operator. E) repressor must not be synthesized. Answer:  C

Section:  8.2

Bloom's Taxonomy:  Understanding

ASMcue Outcome:  4.3

Learning Outcome:  8.7

Global Outcome:  2

16)  Synthesis of a repressible enzyme is stopped by the

A) allosteric transition.

B) substrate binding to the repressor. C) corepressor binding to the operator.

D) corepressor-repressor complex binding to the operator. E) end product binding to the promoter.

Answer:  D

Section:  8.2

Bloom's Taxonomy:  Understanding

ASMcue Outcome:  4.3

Learning Outcome:  8.7

Global Outcome:  2

Figure 8.2